Some useful tips to work out the quantity of cement, sand & aggregate in concrete

This construction video tutorial will provide some useful tips to work out quantity of cement, sand and aggregate in a plane concrete.

The calculation is made on the basis of following dimensions :-

Volume of concrete = 1m3
Here M15 concrete grade is selected with 1:2:4 ratios (cement : sand : aggregates)
Density of cement = 1440 kg/m3
It is known that 1m3 = 35.3147 ft3
Volume of concrete = length x breadth x height = 1x1x1 = 1m3. It is wet volume of concrete To convert it to dry volume, multiply wet volume with 1.54 i.e. 1 x 1.54 = 1.54 m3

Given below, the details on how 1.54 is derived :-

Dry volume for concrete (cement + sand + aggregate) = 54% more than wet volume.
= 100/100 + 54/100 = 1 + .54 = 1.54
= 1.54 x wet volume

To determine the volume of cement in cumec, kg and bags, the following data are required :-

Dry volume of concrete = 1.54 m3
Concrete M15 = 1:2:4 = 1+2+4 = 7
Density of cement = 1440 kg/ m3
1 cement bag = 50 Kg
Apply this formula to find out the volume of cement in cumec (m3) = 1/7x1.54 = 0.22 m3

Apply this formula to find out the volume of cement in Kg = 1/7 x 1.54 x 1440 = 316.8 Kg.
Apply this formula to find out the volume of cement in bags = 316.8/50 = 6.336 bags.

Given below the data upon which the volume of cement in cubic feet (ft3) will be determined :-

Method 1 : 0.22 x 35.3147 = 7.76 ft3
Method 2 : 6.336 x 1.226 = 7.76 ft3

Determine the volume of 1 bag cement with the following formula :-

Density of cement = 1440 kg/ m3
Mass of 1 cement bag = 50 kg
Volume of 1 bag cement = mass/density = 50/1440 = 0.0347 m3
In cubic feet (ft3) = 0.0347 x 35.3147 = 1.226 ft3

To get more details, go through the following construction video.

Video Source TECH@7K