How To Prepare Bar Bending Schedule For Column

In this exclusive civil engineering article, you will get some vital information on how to create steel bar bending schedule for column. Bar Bending Schedule means “Computation of the total steel necessary for developing a building”.

The steel is utilized to allow concrete to be reinforced and for tension requirements. But the quantity of steel necessary for construction, the quantity of steel to be ordered should be determined by bar bending schedule.

In Bar bending schedule table, the bars are arranged for each structural units (beams or columns or slabs or footings etc) and through list is created to indicate the position of the bar in footings, slabs, beams or columns, bar marking (to determine the bar as per the drawing), bar size (length of the bar applied), quantity (number of bars used), cutting length, type of bend and shape of the bar in reinforcement drawings.

The bar bending member in column should be 2.5% of total volume of concrete.

The calculation of bar bending schedule for column is prepared on the basis of the following data :-

• Slab Thickness – 125 mm & 100 mm
• Floor height – 3000 mm or 3 m
• Ground Floor Level – 3300 mm

• Footing Height – 300 mm
• Development Length – 50d
• The column has 6 numbers of 20 mm dia bars
• 8mm stirrups @ 150 mm C/C
• Footing Clear Cover – 40 mm
• Slab Clear Cover – 25 mm

First Step – Determine the length of Vertical Bar

length of Vertical Bar = Development length (Ld) + Height of Ground Level + Floor Heights (1,2,3)+ Slab Thicknesses + Overlap Length (Det.B)

= (50×20)+3300+ (3×3000)+(3×125)+100 +(50×20)
= 14775 mm or 14.78 m

Also Read: How to use BarBeQue software for Reinforcement Bar Bending Schedules for RCC Work

It is the length of one vertical bar. Generally, column reinforcement drawings are not taken into consideration with lapping details.

Second Step – Determine the lapping

Necessary lapping length is 50d = 50 * Diameter of the bar = 50×20 = 1000 mm.

It is assumed that each bar is 12.25 m or 40 feet length (approx).Total Length of Vertical Bar = 14.2 m that is in excess of 12.25 m so each rod is lapped minimum once to achieve the necessary length.

Therefore, the lapping length is included with the total length = 14775+1000 = 15775 mm or 15.78 m

Third Step – Cutting Length of Stirrups

Length of One Hook = 9d (Cutting length of Stirrup = Perimeter of stirrup + Number of Bends + Number of Hooks)

= 2(a+b) + 3 numbers of 90 degree bends + 2 numbers of hooks
= 2(500+200)+(3 x2d)+(2x9d)= 2×700+3x2x20+2x9x20

Cutting length of Stirrup = 1880 mm

Fourth Step – Number of Stirrups

Number of necessary stirrups = (Total length of Column/spacing of stirrups)+1
= (3300+125+3000+125+3000+125+3000+100)/150 + 1
Number of stirrups= 85 nos.
Fifth Step - Bar Bending Schedule

Vertical Bar :-
Diameter of bar = 20 mm
Numbers = 6
Cutting Length = 14.2 m
Total Length = 85.2 m

Stirrups Bar :-
Diameter of bar = 8 mm
Numbers = 85
Cutting Length = 1.88 m
Total Length = 159.8 m